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In fig. 6.2 bac 90° and ad  bc. then

WebMay 18, 2024 · In Fig., ∠BAC = 90° and AD ⊥ BC. The number of right triangles in the figure is (A) 1 (B) 2 (C) 3 (D) 4 geometry class-6 1 Answer +1 vote answered May 18, 2024 by Varun01 (53.6k points) selected May 22, 2024 by Subnam01 (C) 3 We have, ∠BAC = 90° and AD ⊥ BC ∵ ∠BDA = ∠CDA = ∠BAC = 90° ∴ There are 3 right triangles formed in the given … WebABC is an isosceles triangle with AB =AC and D is a point on BC such that AD⊥BC(Fig. 7.13). To prove that ∠BAD=∠CAD,a student proceeded as follows: ΔABDand ΔACD, AB =AC (Given) ∠B=∠C (because AB =AC) and ∠ADB=∠ADC Therefore, ΔABD≅ΔACD(AAS) So, ∠BAD=∠CAD(CPCT) What is the defect in the above arguments? View Answer

In an equilateral triangle ABC (Fig. 6.2), AD is an altitude. Then …

WebIn Fig. 6.2, ∠BAC = 90° and AD BC. Then, a. BD . CD = BC 2 b. AB . AC = BC 2 c. BD . CD = AD 2 d. AB . AC = AD 2. Solution: Given, ∠BAC = 90° Also, AD BC. We know that a … WebIn figure, if ∠BAC =90° and AD⊥BC. Then, (a) BD.CD = BZC² (b) AB.AC = BC² (c) BD.CD=AD² (d) AB.AC =AD² Solution: c) BD.CD=AD² Explanation: From ∆ADB and ∆ADC, According to … gambia ministry of energy https://theosshield.com

MCQ Questions for Class 10 Maths Triangles with Answers

WebIn Fig. 7.238, ∠BAC = 90° and AD ⊥ BC. Then, BD. CD = _________. Q. In figure, ∠BAC=90∘ and segment AD⊥BC. Prove that AD2 =BD×DC. [3 MARKS] Q. In the figure given below, … WebOct 19, 2024 · Then Undefined control sequence \operatorname is equal to (а) 5 (b) 25 (c) (d) Answer 10. In ∠BAC = 90° and AD ⊥ BC. A Then (а) BD.CD = BC² (б) AB.AC = BC² (c) BD.CD = AD² (d) AB.AC = AD² Answer 11. D and E are respectively the points on the sides AB and AC of a triangle ABC such that AD = 2 cm, BD = 3 cm, BC = 7.5 cm and DE BC. WebQuestion In the figure given below,∠BAC=90 0 and AD⊥BC. then AD 2=BD×DC. If the above statement is true then mention answer as 1, else mention 0 if false Medium Solution … black cumin seed australia

In Fig. 6.2, ∠BAC = 90° and AD ⊥ BC. Then - [MCQ

Category:Important Questions for Class 10 Maths Chapter 6 Triangles

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In fig. 6.2 bac 90° and ad  bc. then

In the given figure, ∠BAC = 90° and AD⊥BC. Then, - Sarthaks eConnect

WebMar 29, 2024 · Example 10 In figure, ∠ ACB = 90° and CD ⊥ AB. Prove that BC2/AC2=BD/AD Given:- ΔCAB, ∠ ACB = 90° And CD ⊥ AB To Prove :- BC2/AC2=BD/AD Proof : From theorem 6.7, If a perpendicular is drawn from the vertex of the right angle to the hypotenuse then triangles on both sides of the Perpendicular are similar to the whole triangle and to ...

In fig. 6.2 bac 90° and ad  bc. then

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WebJun 28, 2024 · In the figure, if ∠BAC = 90° and AD ⊥ BC. Then, (A) BD . CD = BC 2 (B) AB . AC = BC 2 (C) BD . CD = AD 2 (D) AB . AC = AD 2 Solution: (C) In ∆ABC, ∠B + ∠BAC + ∠C = … WebByju's Answer Standard X Mathematics Criteria for Similarity of Triangles In the given ... Question In the given figure, if ∠ADE= ∠B, show that ΔADE ∼ΔABC. If AD = 3.8 cm, AE = 3.6 cm, BE = 2.1 cm and BC = 4.2 cm, find DE. Solution In ΔADE and ΔABC, ∠A= ∠A (Common angle) ∠ADE= ∠B (Given) So by AA similarity, triangles are similar. So, by CPCT,

WebIn Fig. 6.13, ∠BAC = 90°, AD ⊥ BC and ∠BAD = 50°, then ∠ACD is (a) 50° (b) 40° (c) 70° (d) 60° 25. If one angle of a triangle is equal to the sum of the other two angles, the triangle is (a) obtuse (b) acute (c) right (d) equilateral 26. WebIn Fig. 6.2, ∠BAC = 90° and AD BC. Then, a. BD . CD = BC 2 b. AB . AC = BC 2 c. BD . CD = AD 2 d. AB . AC = AD 2. Solution: Given, ∠BAC = 90° Also, AD BC. We know that a perpendicular drawn from the vertex of the right angle of a right triangle to its hypotenuse divides the triangle into two triangles which are similar to the whole ...

WebGiven :- First of all we have find and in triangles and respectively. In and . In (given) Now let us find angle CAD from triangle ADC. Here (sum of interior angles of triangle = 180 o). Now let us find angle DBA using triangle ABC WebIn figure, if ∠BAC =90° and AD⊥BC. Then, (a) BD.CD = BZC² (b) AB.AC = BC² (c) BD.CD=AD² (d) AB.AC =AD² Solution: c) BD.CD=AD² Explanation: From ∆ADB and ∆ADC, According to the question, we have, ∠D = ∠D = 90° (∵ AD ⊥ BC) ∠DBA = ∠DAC [each angle = 90°- ∠C] Using AAA similarity criteria, ∆ADB ∼ ∆ADC BD/AD = AD/CD BD.CD = AD 2 2.

WebAug 5, 2024 · In the given figure, ∠A = 90°, AD ⊥ BC. If BD = 2 cm and CD = 8 cm, find AD. (2012; 2024D) Solution: ∆ADB ~ ∆CDA … [If a perpendicular is drawn from the vertex of the right angle of a rt. ∆ to the hypotenuse then As on both sides of the ⊥ are similar to the whole D and to each other ∴ … [∵ Sides are proportional AD 2 = BD , DC

WebAug 15, 2024 · Choose the correct answer from the given four options:1.In Fig. 6.2, Z BAC = 90° and ADI BC. Then,ABDCFig. 6.2… Get the answers you need, now! panditdineshchandras panditdineshchandras 16.08.2024 Math Secondary School answered Choose the correct answer from the given four options: 1. black cumin seed benefits for menWebMar 7, 2024 · In the given figure, angle BAC = 90° and AD perpendicular BC. Then, A)BC.CD = BC² B)AB.AC =BC² C) BD.CD = AD² D)AB.AC = AD² Answer: Option C) BD.CD = AD² … gambia love holidaysWebSolution Verified by Toppr Given:- Let ABCD be the quadrilateral circumscribing the circle with centre O. The quadrilateral touches the circle at point P,Q,R and S. To prove:- … black cumin seed benefits hairWebNov 18, 2024 · In fig 6.2 angle BAC =90° and AD perpendicular to BC Get the answers you need, now! kshitijmishra935 kshitijmishra935 19.11.2024 Math Secondary School answered In fig 6.2 angle BAC =90° and AD perpendicular to BC 1 See answer Advertisement Advertisement dualruksha dualruksha Answer: I hope this is correct answer. black cumin seed for dogsWebIn figure, ∠BAC=90 o and AD⊥BC. Then A BD.CD=BC 2 B AB.AC=BC 2 C BD.CD=AD 2 D AB.AC=AD 2 Easy Solution Verified by Toppr Correct option is C) Given, In ABC, ∠A=90 … gambia money transferWebJun 29, 2024 · In the given figure, ∠BAC = 90° and AD⊥BC. Then, (a) BC.CD = BC2 (b) AB.AC = BC2 (c) BD.CD = AD2 (d) AB.AC = AD2 triangles class-10 1 Answer +1 vote answered … black cumin seed extractWebMar 29, 2024 · Ex 6.2, 4 In figure, DE AC and DF AE. Prove that, prove that 𝐵𝐹/𝐹𝐸 = 𝐵𝐸/𝐸𝐶 Given: DE II AC and DF II AE To prove: 𝐵𝐹/𝐹𝐸=𝐵𝐸/𝐸𝐶 Proof: From (1) and (2) 𝐵𝐹/𝐹𝐸=𝐵𝐸/𝐸𝐶 Hence proved Next: Ex 6.2, 5 Important → Ask a doubt Chapter 6 Class 10 Triangles Serial order wise Ex 6.2 gambia ministry of health logo