In an ap the sum of first n terms is 5n 2/2
WebWe know that in an AP sum of the first n terms Sn = (n/2) {2a+ (n-1)d} and the nth term=a+ (n-1)d So (3n/2) {2a+ (3n-1)d} = (n/2) [2 {a+ (3n+1–1)d}+ (n-1)d] =>6a+9nd-3d = 2a+6nd+nd-d.. (This is after cancelling n/2 both sides =>4a+2nd-2d = 0 => 2a+nd-d = 0…. (1) The ratio of the first 2n termsis equal to the sum of the next 2n terms => WebOct 16, 2024 · The sum of the first n terms of an A.P. is given by Sn = 2n2 + 5n , find the nth term of the A.P. arithmetic progression class-10 1 Answer +1 vote answered Oct 16, 2024 by Ishti (46.5k points) selected Oct 31, 2024 by Anika01 Best answer Sn =2n2 + 5n Taking n = 1, we get S1 = 2 (1)2 + 5 (1) ⇒ S1 = 2 + 5 ⇒ S1 = 7 ⇒ a1 = 7 Taking n = 2, we get
In an ap the sum of first n terms is 5n 2/2
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WebThe sum of the first n terms of an AP is (5n^2/2 + 3n/2). Find its nth term and the 20th term of this AP. asked Jul 9, 2024 in Arithmetic Progression by Anaswara (31.5k points) … WebJan 15, 2024 · If the sum of the first n terms of a series is 5n2 + 2n, then its second term is (A) 7 (B) 17 (C) 24 (D) 42 ... If the sum of the first n terms of a series is 5n 2 + 2n, then its second term is (A) 7 (B) 17 (C) 24 ... terms are in AP whose common difference is 2 and the last (2n + 1) asked Jan 18, 2024 in Binomial theorem by Ritik01 (48.4k ...
WebJul 12, 2024 · Best answer Let Sn denotes the sum of first n terms of the AP. ∴ Sn = 5n - n2 ⇒ ⇒ Sn-1 = 5 (n - 1) - (n - 1)2 = 5n - 5 - n2 + 2n - 1 = 7n - n2 - 6 ∴ nth term of the AP, an = Sn …
WebJul 25, 2024 · Mohammed Owais. 2 years ago. Its bcoz, (Ref=n/2) the sum of any 2 terms of an AP is divided by 2 gets it middle number. example, 3+6/2 is 4.5 which is the middle of these terms and if you … WebThe Sum of the First N Terms of an Ap in `((5n^2)/2 + (3n)/2)`.Find Its Nth Term and the 20th Term Of This Ap. CBSE English Medium Class 10 ... Important Solutions 4010. Question Bank Solutions 26519. Concept Notes & Videos 213. Time Tables 14. Syllabus. The Sum of the First N Terms of an Ap in `((5n^2)/2 + (3n)/2)`.Find Its Nth Term and the ...
WebApr 10, 2024 · Sum of first n terms of an AP. S n = n 2 [ 2 a + ( n − 1) d] Where a =1st term & d =common difference. Or, S n = n 2 [ a + a n] If there are only n terms in an AP, then. a n. …
WebJan 8, 2024 · In an AP the sum of first n terms is 3n^2/2 + 5n/2 find the 25th term.In an AP the sum of first n terms is (3n^2+ 5n)/2 find the 25th term.In an AP the sum o... cinnamon shore port aWebApr 20, 2024 · The sum of the first n term of an AP,denoted by S_n is given by S_n=n^2+8n So n th term of the series will be t_n=S_n-S_(n-1)=n^2+8n-((n-1)^2+8(n-1)) =>t_n=2n-1+8=2n+7 Inserting n=1,2,3.... we get "For "n=1tot_1=2*1+7=9 "For "n=2tot_2=2*2+7=11 "For "n=3tot_3=2*3+7=13 Hence first term t_1=9 and common difference d=t_2-t_1=11-9=2 … cinnamon shore port aransas vacation rentalsWebMar 27, 2024 · Solution For 10] Find the sum of first ' n ' terms of an AP 2 ,8 ,18 ,32 , 11] If α,β and γ are the zeroes of the polynomial P(x)=x3−6x2−x+30 then fin. The world’s only live instant tutoring platform. Become a tutor About us Student login Tutor login. Login. Student Tutor. Filo instant Ask button for chrome browser. ... cinnamon shores corpus christiWebMar 30, 2024 · Given Sn = 2n2 + 3n Taking n = 1 S1 = 2 12 + 3 1 = 2 + 3 = 5 So, Sum of first term of AP is 5 But sum of first term will be the first term So, First term = a = 5 Taking n = 2 in Sn S1 = 2 22 + 3 2 S2 = 2 4 + 6 S2 = 8 + 6 S2 = 14 Sum of first 2 terms is 14 Finding 2nd term Sum of first 2 terms is 14 First term + Second term = 14 5 + a2 = 14 a2 = … cinnamon shores port aransas mapWebApr 20, 2024 · The sum of the first n term of an AP,denoted by Sn is given by. Sn = n2 +8n. So. n th term of the series will be. tn = Sn −Sn−1 = n2 + 8n − ((n −1)2 +8(n − 1)) ⇒ tn = 2n … diák office ingyenWebin an AP the sum of first n terms is 3n2/2 + 13n/2 Solution Verified by Toppr Was this answer helpful? 0 0 Similar questions The first term of two APs are equal and the ratios of … diakomihalis wrestling familyWebJun 28, 2024 · nth term =10n+3 Step-by-step explanation: sn=d/2 n^2+ (a-d)n 5n^2+3n=d/2n^2+ (a-d)n from the equation d/2=5 d=10 (a-d)=3 a-10=3 a=13 first term =13 sum of first two term 2nd term =a+d =13+10 =23 sum of first two term =13+23 =36 third term =a+2d = 13+ (2×10) =13+20 =33 10th term=a+9d =13+ (9×10) =13+90 =103 nth … diakomihalis brothers